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(cos4x-cos2x)/(sin4x-sin2x)...evaluate integral..

(cos4x-cos2x)/(sin4x-sin2x)...evaluate integral..

Grade:11

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear shivanshi

∫(cos4x-cos2x)/(sin4x-sin2x) dx

use  cosA - cosB 

and sinA -sinB formula

intigral become

-∫tan3x dx

= 1/3 ln|cos3x| +c

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