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integrate
∫1 ⁄ x(1+x2)1/2dx
Dear Jithu Prasad
∫x ⁄ x2(1+x2)1/2dx
let (1+x2) =t2
xdx =tdt
so intigral become
∫1/t2 -1 dt
1/2 ln|t-1|/|t+1| + C
1/2 ln|(1+x2)1/2-1|/|(1+x2)1/2+1| + C
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