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integrate { 2x- [2x] }^2 ,limit 0 to 100[x] ,where [.] is G.I.F
0^100[x] ∫( fraction part 2x)^2dx
let 2x=t
2dx=dt
dx=dt/2 x=0 ;t=0
x=100[x] ;t=200[x]
0^200[x] ∫{t}^2 dt/2
(period of fraction part is 1)
200[x]*0^1∫t^2dt/2 = 100[x]/3
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