solve ∫|x+1| from limit -4 to 2 and explain

First we have to remove the modulus sign befor integration.

Part 1:|x+1| is negative in the interval -4 to -1. therefore |x+1| becomes  -x-1

Part 2:and from the interval -1 to 2 |x+1| is x+1.

Therefore integrate |x+1| in above two parts.