Integral Calculus

Definite Integral by Substitution

CBSE 2011 : 2sinxcosxtan^-1(sinx)dx limits pi/2 to 0

Ninad sant

13 Years agoGrade

1 Answer

Sher Mohammad

12 Years ago

$\int_{\frac{\pi }{2}}^0 2 \sin (x) \cos (x) \tan ^{-1}(\sin (x)) \, dx =$ $1-\frac{\pi }{2}$

$\int_{a}^b 2 \sin (x) \cos (x) \tan ^{-1}(\sin (x)) \, dx =\frac{1}{2} \left(2 (\sin (a)-\sin (b))+(\cos (2 a)-3) \tan ^{-1}(\sin (a))-(\cos (2 b)-3) \tan ^{-1}(\sin (b))\right)$

Sher, Mohammad

B.Tech, IIT Delhi

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Definite Integral by Substitution CBSE 2011 : 2sinxcosxtan^-1(sinx)dx limits pi/2 to 0

Ninad sant

1 Answer

Sher Mohammad

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Definite Integral by Substitution

CBSE 2011 : 2sinxcosxtan^-1(sinx)dx limits pi/2 to 0

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