# how to solve the integral of  x^3 /e^x - 1 w.r.t x limits are 0 to infinity

$\int \left(\frac{x^3}{e^x}-1\right) \, dx=e^{-x} \left(-\frac{x^3}{\log (e)}-\frac{3 x^2}{\log ^2(e)}-\frac{6 x}{\log ^3(e)}-\frac{6}{\log ^4(e)}\right)-x$