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x^3/[(x^2)+1]^3.dx
x^2 + 1 = t
diffrntiate both sides
x dx = dt/2
and also, x^2 = t - 1
Now, x^3/[(x^2)+1]^3.dx can be written as {(x)(x^2)/[(x^2)+1]^3.}dx
It will become (t-1)dt/2t3
or (1/2t2)dt - (1/2t3)dt
=Now u can easily integrate and after then replace t by x^2 + 1.
ok
Approve yarrrrrrrrr
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