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Integration of (2+sqrt x)/(x+sqrt x+ 1)^2
apply eulers subsitution
Using x=u2
dx=2u.du
so its:
integration of (2+u)/(u2+u+1).dx
now, the numerator is derivative of denominator so its:
u2 * log(u2+u+1)
because
intergation of f''(x)/f(x) = log[f(x)]
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