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0 to 2pi definite integration of 1/(1+e^sinx)

0 to 2pi definite integration of 1/(1+e^sinx)

Grade:12

3 Answers

upasana bhuyan
29 Points
8 years ago

do it using properties of definite integrals

gauhar singh
7 Points
8 years ago

pi

arre yeh properties se hota hai integral F(x) o to 2pi is equal to integral of F(x) from 0 to pi plus integral F(2pi-x) from 0 to pi

sin(2pi-x)= -sinx

e-sinx=1/esinx

lcm le le aur denominator numerator cancel, integral 1 hota hai 0 to pi

k sesi preetam
7 Points
8 years ago

according to the properties of definite integration  

(lim 0 to a) f(x) dx = ∫(lim 0 to a) f(a-x)dx.  Using this property we get the answer to be pi.

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