1/sinx+secx
Prabhudananda Sahoo , 13 Years ago
Grade 11
Integral Calculus> indefinite-integral...
1 Answers
Vidyasagar Mohanraj
integral of sec(x) = log(tanx + secx)
integral 1/sin(x) = [log(cosx + 1) - log(cosx - 1)]
then add the both
Approved Last Activity: 13 Years ago
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