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Grade: 12 

                        
integral 0 to 1 [2x]
8 years ago

Answers : (3)

TANAYRAJ SINGH CHOUHAN
65 Points 
							
∫01[2x] dx= [2x2/2] 0 to 1


           = [x2] 0 to 1


           = 12 - 02


           = 1
8 years ago
Anirudh K
18 Points 
							
sorry sir.but i didnt understand this step-([2x]=[2x^2/2]) by the way sir,there is no 1 in answer choices
8 years ago
Kumar Gaurav
33 Points 
							
2
8 years ago
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