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integral 0 to 1 [2x]
∫01[2x] dx= [2x2/2] 0 to 1 = [x2] 0 to 1 = 12 - 02 = 1
∫01[2x] dx= [2x2/2] 0 to 1
= [x2] 0 to 1
= 12 - 02
= 1
sorry sir.but i didnt understand this step-([2x]=[2x^2/2]) by the way sir,there is no 1 in answer choices
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