integrating (xcube.taninverse x)dx

Integral x^3taninversex dx

Integratinga by part by taking taninverse x as 1^st func tion and x^3 as second function

=tan inverse x. x^4/4 –intergral (1/(1+x^2) .x^4/4 dx

=1/4 .x^4.taninverse x -1/4integral (x^4/(1+x^2) dx

=x^4/4 taninversex-1/4 integral (x^2-1+1/(1+x^2) dx

=x^4/4 taninversex-1/4{x^3/3-x+taninverse(x)

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty