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integrating (xcube.taninverse x)dx
Integral x^3taninversex dx
Integratinga by part by taking taninverse x as 1st func tion and x^3 as second function
=tan inverse x. x^4/4 –intergral (1/(1+x^2) .x^4/4 dx
=1/4 .x^4.taninverse x -1/4integral (x^4/(1+x^2) dx
=x^4/4 taninversex-1/4 integral (x^2-1+1/(1+x^2) dx
=x^4/4 taninversex-1/4{x^3/3-x+taninverse(x)
Thanks & Regards
Rinkoo Gupta
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