Rinkoo Gupta12 Years agointegral cosx/(sinx+cosx)=integral cosx(cosx-sinx)/(cosx+sinx)(cosx-sinx)integral (cos^2x-sinxcosx)/cos^2x-sin^2x) dx=integral ((1+cos2x)/2)/cos2x-((sin2x)/2)/cos2x=1/2integral(sec2x+1)-1/2integraltan2x dx=1/4logmod(sec2x+tan2x)+x/2+1/4logmodcos(2x)Thanks & RegardsRinkoo GuptaAskIITians Faculty