Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
debadutta mishra Grade: 11

we r given that the curves y =integation from -infinity to x f(t)dt through the point (0,1/2) and y=f(x),where f(x)>0 and f(x) is differntiable for x belongs to R through (0,1).If tangents dranw to both the curves at the point having equal abscissae intersect on the same point on x axis then 

no. of solutions f(x)=2ex = ?

6 years ago

Answers : (2)

14 Points

hey,this question is in the GRAND MASTERS PACKAGE.Have you completed all the questions of GMP?

6 years ago
Jit Mitra
25 Points

From the first relation,


dy/dx = f(x)

Equation of tangent at (0,1/2):


(y-0.5)/(x-0) = f(x)

or, x.f(x) = y-1/2


From the second relation,


dy/dx = d(f(x))


Equation of tangent at (0,1):


(y-1)/(x) = d(f(x))


x.d(f(x)) = y-1


Note (0,1/2) and (0,1) has same abscissae, so,

On the x-axis, let the common point be (h,0)

Both the equations should satisfy this point.


h.f(h) = -0.5          ............(i)

h.d(f(h)) = -1           ...........(ii)


dividing (i) and (ii),


d(f(h))/f(h) = 2

Integrating both sides,


ln (f(h)) = 2h + c

f(h) = e^(2h+c)


the function is f(x)=e^(2x+c)


Given the y=f(x) passes through (0,1), putting the values, in the above relation,


1 = e^(c)

or, c = 0


therefore the funtion is, f(x) = e^(2x)





f(x) = 2e^(x)

or, e^(2x) = 2.e^(x)

or, e^(x) = 2

or, x = ln2


so, i get just one solution. And i m really curious to know the answer. :) ..

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details