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let y=y(t) be a solution to the differential equation y'+2ty=t^2,then lim(t tends to infinity) [y/t] is?
Given differential equation is,
dy/dt + 2t y = t2
This is a linear differential equation where P(t) = 2t and Q(t) = t2,
So, the solution of this differential equation will be given by
After solving this, you need to simply find greatest integer of y/t, i.e.,[y/t] and take limit t -> .
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