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I=∫xdx/(√7x-10-x2)3

B.V.Suhas Sudheendhra , 14 Years ago
Grade 12
anser 1 Answers
Chetan Mandayam Nayakar

7x-10-x2=2.25-(x-3.5)2

let x-3.5=t

I=∫(t+3.5)dt/(√2.25-t2)3=∫tdt/(√2.25-t2)3+∫(3.5)dt/(√2.25-t2)3

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