Chetan Mandayam NayakarApproved Tutor Answer14 Years ago7x-10-x2=2.25-(x-3.5)2 let x-3.5=t I=∫(t+3.5)dt/(√2.25-t2)3=∫tdt/(√2.25-t2)3+∫(3.5)dt/(√2.25-t2)3