I=∫[x+√(1+x2)]15dx/√(1+x2)
I=∫[x+√(1+x2)]15dx/√(1+x2)
B.V.Suhas Sudheendhra , 14 Years ago
Grade 12
Integral Calculus> Integrations...
1 Answers
shamsheer shaik
take x = tant
on simplification we have = integral of (sect + tant )^14 sect(sect + tant) dt
since the derivative of sect + tant is sect(sect + tant) therefore integral of required quantity is
(sect + tant)^15 divided by 15 now subsitute tant = x hence we have requied quantiy .
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