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I= ∫ [x+√(1+x 2 )] 15 dx/√(1+x 2 )

I=[x+√(1+x2)]15dx/√(1+x2)

Grade:12

1 Answers

shamsheer shaik
34 Points
10 years ago

take x = tant

 on simplification we have = integral of (sect + tant )^14 sect(sect + tant) dt 

 since the derivative of sect + tant is sect(sect + tant) therefore integral of required quantity is

  (sect + tant)^15 divided by 15 now subsitute tant = x hence we have requied quantiy .

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