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∫ dx/x2-1
In the above equation before - one is x square.
1/(x^2 -1)=1/(x+1)(x-1)=(1/2)((1/(x+1))-(1/(x-1)))
Answer=(1/2)ln|(x+1)/(x-1)|
1/(x^2 -1)=1/(x+1)(x-1)=(1/2)((1/(x-1))-(1/(x+1)))
Answer=(1/2)ln|(x-1)/(x+1)|
this one is the right answer dude.....well all the best...:)
integration of 1/(1-x2) is tan-1 x.
Thus here in this problem, if we take a minus sign common,then we will get the equation in this form. thus the answer is
-tan-1x
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