Please solve this-

In (a=0, b=1) { [log(1+x)] / (1+x^2) } dx

put x=tana then dx=sec^2ada , integral 0 to pi/4  log(1+tana)sec^2a/1+tan^2a

 = log(1+tana) on applying integral a-b f(x) = integral a-b f(a+b-x) we get required definite integral as( pi/8)log2