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Please solve this-
In (a=0, b=1) { [log(1+x)] / (1+x^2) } dx
put x=tana then dx=sec^2ada , integral 0 to pi/4 log(1+tana)sec^2a/1+tan^2a
= log(1+tana) on applying integral a-b f(x) = integral a-b f(a+b-x) we get required definite integral as( pi/8)log2
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