∫[√(sin 4 x + cos 4 x)]/[sin 3 x*cosx] dx

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&int;[&radic;(sin 4 x + cos 4 x)]/[sin 3 x*cosx] dx

Sher Mohammad · Answer

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∫[√(sin 4 x + cos 4 x)]/[sin 3 x*cosx] dx

∫[√(sin⁴x + cos⁴x)]/[sin³x*cosx] dx

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∫[√(sin 4 x + cos 4 x)]/[sin 3 x*cosx] dx

∫[√(sin4x + cos4x)]/[sin3x*cosx] dx

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∫[√(sin⁴x + cos⁴x)]/[sin³x*cosx] dx