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integrate (x2 + x)/(ex+x+1)2 w.r.t x
Hi Suchita,
take ex common from denominator,
then you have............. e-xxe-x(x+1)/(1+xe-x+e-x)2
Make the substitution, 1/(1+xe-x+e-x) = t, and you will get
xe-x/(1+xe-x+e-x)2dx = dt, and xe-x+e-x = (1/t)-1.
So after this substitution, you have Integral of [(1/t)-1] = lnt - t + Const. And substitute for t from above.
Hope that helps.
All the best,
Regards,
Ashwin (IIT Madras).
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