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Hi Ashutosh,
Please note that this can be integrates only when "n" is a natural number.
So now (1-x3)n can be binomially expanded, and you will have
1 - nC1x3 + nC2x6 - nC3x9 + ............ (-1)n nCnx3n
Now each of the terms can be easily intergrated individually using the integration of xn = xn+1/(n+1).
Hope that helps,
All the best,
Regards,
Ashwin (IIT Madras)
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