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∫xsinx2esecxΛ2/cos2x2 dx=? try to go through ILATE form .plz reply soon!!!
take t=esecx^2
then differentiate it,
dt=esecx^2.secx2.tanx2.2x.dx
dt/2=esecx^2secx2tanx2.x.dx
in the integration part,(ie) in your question
the Nr can be written as,
=(x tanx2 esecx^2/cosx2 ) dx
=x secx2 tanx2 esecx^2dx
=dt/2
after removing the integration symbol,(ie) after doing integration
it will become
=t/2
=esecx^2/2
this is the answer
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