∫xsinx2esecxΛ2/cos2x2 dx=? try to go through ILATE form .plz reply soon!!!
Last Activity: 13 Years ago
take t=esecx^2
then differentiate it,
dt=esecx^2.secx2.tanx2.2x.dx
dt/2=esecx^2secx2tanx2.x.dx
in the integration part,(ie) in your question
the Nr can be written as,
=(x tanx2 esecx^2/cosx2 ) dx
=x secx2 tanx2 esecx^2dx
=dt/2
after removing the integration symbol,(ie) after doing integration
it will become
=t/2
=esecx^2/2
this is the answer
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 2 Years ago
Last Activity: 3 Years ago