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∫xsinx 2 e secxΛ2 /cos 2 x 2 dx=? try to go through ILATE form .plz reply soon!!!

∫xsinx2esecxΛ2/cos2x2 dx=?  try to go  through ILATE form .plz reply soon!!!SmileSmile

Grade:12

1 Answers

Nanda RJ
12 Points
9 years ago

take t=esecx^2 

then differentiate it,

dt=esecx^2.secx2.tanx2.2x.dx

dt/2=esecx^2secx2tanx2.x.dx

in the integration part,(ie) in your question

the Nr can be written as,

=(x tanx2 esecx^2/cosx2 ) dx

=x secx2 tanx2 esecx^2dx

=dt/2

after removing the integration symbol,(ie) after doing integration

it will become 

=t/2

=esecx^2/2

this is the answer

 

 

 

 

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