Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

how are we supposed to find the integration of log x upon {(1+log x) the whole square}

how are we supposed to find the integration of


log x upon {(1+log x) the whole square}

Grade:

2 Answers

rajan jha
49 Points
10 years ago
Let logx =t,then e^t=x =>e^tdt=dx then intg becomes te^tdt/(1+t)^2 now use the formula =>§e^x( f(x)+f'(x))dx=e^xf(x).where §=integration.
Om Puri Gosain
26 Points
10 years ago

Put log x + 1 = t => log x = t - 1 => dx = e^t dt answer is [ x / ( log x + 1 )]

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free