how are we supposed to find the integration of
log x upon {(1+log x) the whole square}
how are we supposed to find the integration of
log x upon {(1+log x) the whole square}
Madhuri A. , 14 Years ago
Grade
Integral Calculus> INTEGRATION...
2 Answers
rajan jha
Let logx =t,then e^t=x
=>e^tdt=dx
then intg becomes te^tdt/(1+t)^2 now use the formula
=>§e^x( f(x)+f'(x))dx=e^xf(x).where §=integration.
Om Puri Gosain
Put log x + 1 = t => log x = t - 1 => dx = e^t dt answer is [ x / ( log x + 1 )]
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