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the ans is x4/7+1/2x+c. for this iusrd the method of transformations . in this question i done this transformation:
∫x3/1+x5 dx then x5 can be written as x2.x3 so then by adjustment method we can write it as;1/x3∫x3.x3/1+x2.x3. i.e 1/x3 ∫x6/1+x5 then by deviding we get 1/x3 ∫x6 + x then by integ. we get 1/x3( x7/7+x2/2) then ans isx4/7+1/2x + c. do u like the complete method , if u like this plz approve by clicking yes!!!
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