INTEGRATION OF x^3/1+x^5

the ans is x⁴/7+1/2x+c.  for this iusrd the method of transformations . in this question i done this transformation:

                                                     ∫x³/1+x⁵ dx  then x⁵ can be written as x².x³  so  then by adjustment method we can write it as;1/x³∫x³.x³/1+x².x³. i.e 1/x³ ∫x⁶/1+x⁵  then by deviding  we get 1/x³ ∫x⁶ + x   then by integ. we get 1/x³( x⁷/7+x²/2) then ans isx⁴/7+1/2x + c.   do u like the complete method , if u like this plz approve by clicking yes!!!