Show that integral of
∫ dx / [ (x+1) 1/3 + (x+1) 1/2 ] = 2t3 - 3t2 + 6t - log|1+t| +c where t = (x+1) 1/6
Show that integral of
∫ dx / [ (x+1) 1/3 + (x+1) 1/2 ] = 2t3 - 3t2 + 6t - log|1+t| +c where t = (x+1) 1/6
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Last Activity: 2 Years ago
Last Activity: 2 Years ago
Last Activity: 2 Years ago
Last Activity: 2 Years ago