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vikas askiitian expert
Last Activity: 14 Years ago
integral of e^x.(x^2-x+1)/(x^2+1)3/2
above expression can be rewritten as e^x.([x^2+1]/[x^2+1]^3/2 + [-x/(x^2+1)3/2])
integral of e^x(fx + dfx/dx) =e^x.fx +c
so ans is e^x.1/(x^2+1)^1/2
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