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integration of sinx/sin(x-A) = Bx + C log sin(x-A) + D then values of B and C are 1) (-sinA , cosA) 2) ( cos A, sinA) 3) ( sinA , cosA) 4) (-cos A, sinA)

integration of sinx/sin(x-A) = Bx + C log sin(x-A) + D


then  values of B and C are


1) (-sinA , cosA)


2) ( cos A, sinA)


3) ( sinA , cosA)


4) (-cos A, sinA)

Grade:12

1 Answers

Pramod J AskiitiansExpert-IIT-B
36 Points
12 years ago

Dear student,

let x-A = t

=> sint+A/sint = cos A + sinAcos t/sin t

integration of the eqn. = t*cos A + sin A*log sin t

=> B = cos A C = sin A

option 2 is correct

i hope it explains

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