∫Sin|x|.dx=?

Limits are from -∏/2 to ∏/2

a)0 b)1 c)2 c)4

∫sinlxl.dx from -pi/2 to pi/2 =2∫sin(x).dx from 0 to pi/2 =2(cos0 - cos(pi/2))=2

let apply the graphical approach to it:

where 1) we draw a graph of sinx  -pie/2 to +pie/2  then x at mode that's why  -ve side of this graph is cancelled out and its mirror image will be appeared upward . then integrate the function sinx :

∫sinx (-∏/2 to 0) + ∫sinx (0 to ∏/2)

cos-∏/2-cos0+ cos∏/2-cos0

1+1

=2