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∫Sin|x|.dx=?
Limits are from -∏/2 to ∏/2
a)0 b)1 c)2 c)4
∫sinlxl.dx from -pi/2 to pi/2 =2∫sin(x).dx from 0 to pi/2 =2(cos0 - cos(pi/2))=2
let apply the graphical approach to it:
where 1) we draw a graph of sinx -pie/2 to +pie/2 then x at mode that's why -ve side of this graph is cancelled out and its mirror image will be appeared upward . then integrate the function sinx :
∫sinx (-∏/2 to 0) + ∫sinx (0 to ∏/2)
cos-∏/2-cos0+ cos∏/2-cos0
1+1
=2
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