0

Guest

Courses New

Let for all n belonging to real number,n-2>=2ln n,then the minimum value of the area bound by the curve |y|+1/n

Let for all n belonging to real number,n-2>=2ln n,then the minimum value of the area bound by the curve |y|+1/n<=e^ -|x| is 2 sq. unit. True or false

Grade:12

1 Answers

Ramesh V
70 Points
13 years ago

From n-2 >= 2*ln(n) 

we can say n> 0  which also mean:  n-1 > 0

Now from the curve
  |y|+1/n <= e-|x|   or           |y| <= e-|x| +1/n

 

Now the graph of e-|x|  is symmetric about Y axis 

for 1/n > 0 ;

CASE 1: lets  take least value 1/n = 0

so,   |y| <= e-|x|

For , |y| <= e-|x|  the area bounded is  2*integral of e-|x| with limits from 0 to infininty

so area is 2 sq. units

 

CASE 1: lets  take  value 1/n more than 0

 

So so |y| <= e-|x| - 1/n

here e-|x| - 1/n becomes negative as shown in graph

but |y| is always positive which can never be less than a negative no.

so case 2 is not possible

hence area bounded is 2 sq. units and its TRUE

Think You Can Provide A Better Answer ?

Other Related Questions on Integral Calculus

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More