Integrate {[2x-(5(4x-5))1/2]1/2 +[2x+(5(4x-5))1/2]1/2}within limits 2 to 3.a.[7*(3^1/2)+3*(5^1/2)]/3*(2^1/2)b.4*(2^1/2)c.4*(2^1/2)+4/3d.[7*(7^1/2)-2*(5^1/2)]/3*(2^1/2)

Let 5(4x-5) = m²

           20 dx = 2m dm

integral {1/10^3/2 * [( m²-10m+25)^1/2 + ( m²+10m+25)^1/2] * m} dm with limits from 15^1/2 to 35^1/2

                        = integral {1/10^3/2 * [2m] * m} dm with limits from 15^1/2 to 35^1/2

                        = integral {1/(5*10^1/2) * m²} dm with limits from 15^1/2 to 35^1/2

                       = [ 35*35^1/2 - 15*15^1/2/(15*10^1/2)

                       = [ 7*7^1/2 - 3*3^1/2]/(3*2^1/2)

the final answer is : [ 7*7^1/2 - 3*3^1/2]/(3*2^1/2)       which in not in options above
I think the question posted is wrong