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Integrate {[2x-(5(4x-5)) 1/2 ] 1/2 +[2x+(5(4x-5)) 1/2 ] 1/2 } within limits 2 to 3. a.[7*(3^1/2)+3*(5^1/2)]/3*(2^1/2) b.4*(2^1/2) c.4*(2^1/2)+4/3 d.[7*(7^1/2)-2*(5^1/2)]/3*(2^1/2)
Let 5(4x-5) = m2 20 dx = 2m dm integral {1/103/2 * [( m2-10m+25)1/2 + ( m2+10m+25)1/2] * m} dm with limits from 151/2 to 351/2 = integral {1/103/2 * [2m] * m} dm with limits from 151/2 to 351/2 = integral {1/(5*101/2) * m2} dm with limits from 151/2 to 351/2 = [ 35*351/2 - 15*151/2/(15*101/2) = [ 7*71/2 - 3*31/2]/(3*21/2) the final answer is : [ 7*71/2 - 3*31/2]/(3*21/2) which in not in options above I think the question posted is wrong
Let 5(4x-5) = m2
20 dx = 2m dm
integral {1/103/2 * [( m2-10m+25)1/2 + ( m2+10m+25)1/2] * m} dm with limits from 151/2 to 351/2
= integral {1/103/2 * [2m] * m} dm with limits from 151/2 to 351/2
= integral {1/(5*101/2) * m2} dm with limits from 151/2 to 351/2
= [ 35*351/2 - 15*151/2/(15*101/2)
= [ 7*71/2 - 3*31/2]/(3*21/2)
the final answer is : [ 7*71/2 - 3*31/2]/(3*21/2) which in not in options above I think the question posted is wrong
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