∫cos³x e^log(sinx) dx is equal to

∫cos³x e^log(sinx) dx                            put cosx=t

=∫cos³x sinx dx                                diffrentiating both sides

=-∫t^{3 dt}                                                       -sinxdx=dt  ,   sinxdx=-dt

=-t⁴/4

=-cos^4x/4

^{plz approve if u like...}