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Using integration find the area of the triangular region whose sides have the equations
y=2x+1
y=3x+1
x=4
Pls reply with the best soln as fast as possible !!!
Always gonna be approved !!!
y = 2x + 1 ..............1
y = 3x + 1 ..............2
x = 4 ..........3
line 1 & 2 intersect at P = (0,1)
now , both of these lines are intersected by line 3 so let point of
intersection be Q,R then
P = (4,9) (intersection of line 1 with x = 4)
Q = (4,13) (intersection of line 2 with x = 4)
now area bw all these lines is area of triangle formed by P,Q,R
A = L2 - L2 dx lim from 0 to 4
A = (3x+1)-(2x+1) lim from 0 to 4
A = xdx lim from 0 to 4
A = 8 square units
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