Using integration find the area of the triangular region whose sides have the equationsy=2x+1y=3x+1x=4Pls reply with the best soln as fast as possible !!!Always gonna be approved !!!

y = 2x + 1                ..............1

y = 3x + 1                   ..............2

x = 4                   ..........3

line 1 & 2 intersect at P = (0,1)

now , both of these lines are intersected by line 3 so let point of

intersection be Q,R then

P = (4,9)                          (intersection of line 1 with x = 4)

Q = (4,13)                       (intersection of line 2 with x = 4)

now area bw all these lines is area of triangle formed by P,Q,R

A = L₂ - L₂ dx lim from 0 to 4

A = (3x+1)-(2x+1)     lim from 0 to 4

A = xdx      lim from 0 to 4

A = 8 square units

Approved