vikas askiitian expert
Last Activity: 14 Years ago
y11 - 3y1/x = x
d/dx (y1) - 3y1/x = x ..................1
put y1 = z theneq 1 becomes
dz/dx - 3z/x = x ..............2
now this is a linear differential equation withintegration factor = 1/x3
z/x3 = x/x3 dx
z/x3 = (1/x2)dx = -1/x + c1
z = -x2 + c1x3 ...................3
now , dy/dx = z so
dy/dx = -x2 + c1x3
dy = (-x2 + c1x3)dx
y = -x3/3 + c1x4/4 + c2 .................5
this is the required equation
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