Join now for JEE/NEET and also prepare for Boards Learn Science & Maths Concepts for JEE, NEET, CBSE @ Rs. 99! Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
please explain in detailed steps the general solution of the following differential equation. given equation: y"-3y'/x=x solution: C1x^4/4-x^3/3+C2 required : detailed steps in the solution of the above
Dear student,
Let y=e^mx
dy/dx=me^mx
2y/dx2=m2e^mx
Now substitute this and solve the equation......
y11 - 3y1/x = x
d/dx (y1) - 3y1/x = x ..................1
put y1 = z theneq 1 becomes
dz/dx - 3z/x = x ..............2
now this is a linear differential equation withintegration factor = 1/x3
z/x3 = x/x3 dx
z/x3 = (1/x2)dx = -1/x + c1
z = -x2 + c1x3 ...................3
now , dy/dx = z so
dy/dx = -x2 + c1x3
dy = (-x2 + c1x3)dx
y = -x3/3 + c1x4/4 + c2 .................5
this is the required equation
approve if u like my ans
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !