sir, definite integral (0 to pai/2 logsinx dx) answer possible hai ya nahi?

ans is -(pi/2)log2  &  is possible

approve if u like it

yah answer is possible........

log sinx+ log cos=log(sinxcox)+logsin2x-log2

2x=z

2dx=dz

limit is 0 to pi...........

adjust 1/2 which is comes from 2dx=dz with pi then limit gonna be 0 to pi/2 integration log(sinz)dz which is log(sinx)dx=i

2i=i-log2integration o to pi/2 dx

then i think you can easily solve......... hobei amar

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