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Its an old IIT-JEE question [Paper 1,JEE 2008,Q.20] Consider the function defined implicitly by y^3 - 3y + x =0 on various intervals. If x belongs to (-2,2)the equation implicitly defines a unique real valued differentiable function y=g(x) satisfying g(0)=0 then (I'm writing in words because i can't get the symbols) Integral(-1 to +1) g'(x) = [g'(x) is derivative of g(x)] answer given is 2g(1). How to get it? Its an old IIT-JEE question [Paper 1,JEE 2008,Q.20] Consider the function defined implicitly by y^3 - 3y + x =0 on various intervals. If x belongs to (-2,2)the equation implicitly defines a unique real valued differentiable function y=g(x) satisfying g(0)=0 then (I'm writing in words because i can't get the symbols) Integral(-1 to +1) g'(x) = [g'(x) is derivative of g(x)] answer given is 2g(1). How to get it?
Dear student, y3 - 3y + x = 0 Draw graph {first draw y = 3x - x3 & then reflect in y = x line} Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi sagarsingh24.iitd@gmail.com
Dear student,
y3 - 3y + x = 0 Draw graph
{first draw y = 3x - x3 & then reflect in y = x line}
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi sagarsingh24.iitd@gmail.com
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Askiitians Expert
Sagar Singh
B.Tech, IIT Delhi
sagarsingh24.iitd@gmail.com
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