 Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        There is a line through the origin that divides the region bounded by the parabola y = 3 x - 8 x^2 and the x-axis into two regions with equal area. What is the slope of that line?`
8 years ago

## Answers : (1)

```							let eq of line is y=mx            ...........1
eq of curve y = 3x-8x2           ................2
it will intersect the curve at P & Q ...
solving 1 & 2
x = 0 , (3-m)/8
y = 0 , m(3-m)/8
P = (0,0)  &  Q =[ (3-m)/8 , m(3-m)/8 ]
now x axis cuts the parabola at S = (3/8 , 0)
area bw parabola & x axis is A1 = (3x-8x2)dx         lim 0 to 3/8
=9/128 units
now area bw line & parabola is A2 = (3x-8x2 - mx)dx       lim 0 to (3-m)/8
= (3-m)3/384 units
now since x axis divides the area in two equal parts so
A2 = 2 A1
(3-m)3/384 = 2(9/128)
(3-m)3 = 27*2
m = 3(1-21/3)

```
8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Integral Calculus

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions