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1/1+x^3 .dx


Thank you.

7 years ago

Answers : (1)

vikas askiitian expert
510 Points
							

dear balaram

1+x3 = (1+x)(1+x2-x)

now integral becomes

I = dx/(1+x)(1+x2-x)

now use partial fraction 

1/(1+x)(1+x2-x) = A/(1+x) + (Bx+c)/(1+x2-x)

find A,B,C & then integrate it ...

approve my ans if u like it

 

7 years ago
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