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cosx/(1-sinx)^2(2+sinx) wrt dx

ritu khatri , 14 Years ago
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vikas askiitian expert

Last Activity: 14 Years ago

I  =cosxdx/(1-sinx)2(2+sinx)

put sinx = t

cosxdx =dt

I = dt/(1-t)2(2+t)

now apply  partial fraction and then integrate & get the result

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