1/x2+5

Dear Samar

I=∫dx/x² + 5

I=∫dx/x²+(√5)²

use formula

I=∫dx/x²+a²  = 1/a * tan^-1x/a + C

hence I= 1/√5 * tan^-1x/√5  + C

All the best.

AKASH GOYAL

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integration of 1/(x²+a²) =tan^-1 (x/a) /a    + c

we have ,integration of 1/x²+(sqrt5)²

                  I =tan^-1(x/sqrt5) /sqrt5  + c   ans