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integrate (1+tanx)dx/(1-tanx)

Aparna Tiwari , 14 Years ago
Grade 12
anser 1 Answers
vikas askiitian expert

Last Activity: 14 Years ago

I= {1+tanx/1-tanx}dx

I={(sinx+cosx)/(cosx-sinx)}dx

put cosx-sinx=t then after differentiatng

(sinx+cosx)dx=-dt

I=-dt/t

I=-logt + c

I=-log(cosx-sinx) + c

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