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integrate (1+tanx)dx/(1-tanx)

integrate (1+tanx)dx/(1-tanx)

Grade:12

1 Answers

vikas askiitian expert
509 Points
13 years ago

I= {1+tanx/1-tanx}dx

I={(sinx+cosx)/(cosx-sinx)}dx

put cosx-sinx=t then after differentiatng

(sinx+cosx)dx=-dt

I=-dt/t

I=-logt + c

I=-log(cosx-sinx) + c

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