integrate (1+tanx)dx/(1-tanx)
Aparna Tiwari , 14 Years ago
Grade 12
Integral Calculus> indefinite integrals
1 Answers
vikas askiitian expert
Last Activity: 14 Years ago
I= {1+tanx/1-tanx}dx
I={(sinx+cosx)/(cosx-sinx)}dx
put cosx-sinx=t then after differentiatng
(sinx+cosx)dx=-dt
I=-dt/t
I=-logt + c
I=-log(cosx-sinx) + c
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