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2 (square) Q - integration (from sin x to 1) t f(t) dt = 1-sinx, for all x belongs to [ 0, pi/2) then f ( 1/root 3) is.

                                                                      2 (square)


Q- integration (from sin x to 1) t  f(t) dt  = 1-sinx, for all x belongs to [ 0, pi/2) then f ( 1/root 3) is.

Grade:12

4 Answers

Anil Pannikar AskiitiansExpert-IITB
85 Points
10 years ago

Dear Kanika,

 

 differentiate both sides -

-sinx*f(sinx)* cosx = -cosx

or,  f(sinx) = 1/sinx

put sinx = X

then,  f(X) = 1/X

so, f(1/sqrt.3) = sqrt.3

 

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Askiitians Expert

Anil Pannikar

IIT Bombay

vikas askiitian expert
509 Points
10 years ago

differentiating  both sides wrt x

 we get

            -cosxsinxf(sinx)=-cosx

                      f(sinx)=1/sinx

                     f(t)=1/t

                      f(1/root3)=root3               ans

 

Devasish Bindani
45 Points
10 years ago

the ans i got is root3*(1-sinx) if it is not correct then please send me the answer and correct explanation for it

Vivek Nigam
28 Points
10 years ago

i think you shud revise bansal notes properly....you can easliy get the solution

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