Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
2 (square)
Q- integration (from sin x to 1) t f(t) dt = 1-sinx, for all x belongs to [ 0, pi/2) then f ( 1/root 3) is.
Dear Kanika,
differentiate both sides -
-sinx*f(sinx)* cosx = -cosx
or, f(sinx) = 1/sinx
put sinx = X
then, f(X) = 1/X
so, f(1/sqrt.3) = sqrt.3
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Askiitians Expert
Anil Pannikar
IIT Bombay
differentiating both sides wrt x
we get
-cosxsinxf(sinx)=-cosx
f(sinx)=1/sinx
f(t)=1/t
f(1/root3)=root3 ans
the ans i got is root3*(1-sinx) if it is not correct then please send me the answer and correct explanation for it
i think you shud revise bansal notes properly....you can easliy get the solution
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !