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integration of [t^4+1]1/2.dt

integration of [t^4+1]1/2.dt

Grade:11

1 Answers

Menka Malguri
39 Points
9 years ago

∫(t4+1)/2 dt

=∫(t4/2)dt+∫(1/2)dt

=(1/2)(t5/5) +(1/2)t+c

=t5/10 + t/2 +c

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