Grade 11Integral Calculus
integration of [t^4+1]1/2.dt
1 Answer
Menka Malguri
∫(t4+1)/2 dt
=∫(t4/2)dt+∫(1/2)dt
=(1/2)(t5/5) +(1/2)t+c
=t5/10 + t/2 +c
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