∫(1-x² /x-2x²)dx

Do it by partial fraction,
∫(1-x2 /x-2x2)dx can be written as:
(1-x)*(1 +x)/x*(1 -2x)dx
= A/x + B/(1 -2x)

(1 -x) (1 +x) =A(1- 2x) + B(x)
Put x= 1, -1 and get the values of A nd B and then integerate.
Answer will ome in lagarith form.