Flag Integral Calculus> 1 ∫tan 8 ×sec 4 dx evaluate the following...
question mark

1 ∫tan8×sec4dx
evaluate the following
2 ∫(4x-3)÷(x2+3x+8) dx
evaluate

Prathibhaa P G , 7 Years ago
Grade 11
anser 1 Answers
Khimraj

Last Activity: 7 Years ago

I = ∫tan8×sec4xdx
I =  ∫tan8×(1+tan2x)sec2xdx
Let tanx = t
then sec2xdx = dt
So I = ∫t8(1+t2)dt
I = ∫(t8+t10)dt
I = t9/9 + t11/11 +c
put t = tanx
So I = tan9x/9 + tan11x/11 +c.
Hope it clears. If you like answer then please approve it.
 
 

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments