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Flag Integral Calculus> 1 ∫tan 8 ×sec 4 dx evaluate the following...
question mark

1 ∫tan8×sec4dx
evaluate the following
2 ∫(4x-3)÷(x2+3x+8) dx
evaluate

Prathibhaa P G , 8 Years ago
Grade 11
anser 1 Answers
Khimraj
I = ∫tan8×sec4xdx
I =  ∫tan8×(1+tan2x)sec2xdx
Let tanx = t
then sec2xdx = dt
So I = ∫t8(1+t2)dt
I = ∫(t8+t10)dt
I = t9/9 + t11/11 +c
put t = tanx
So I = tan9x/9 + tan11x/11 +c.
Hope it clears. If you like answer then please approve it.
 
 
Last Activity: 8 Years ago
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