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Zn2+dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M)1) Zn(OH)22) ZnO3) Na2ZnO24) all the above

sneha singh , 11 Years ago
Grade 12
anser 1 Answers
Akshay Meena

Last Activity: 11 Years ago

Zn+2 + 2NaOH -----> Zn(OH)2 + 2Na+
Zinc Hydroxide dissolve in excess alkali because it is also an amphoteric hydroxide and therefore reacts to form solumble Sodium Zincate.
Zn(OH)2 + 2NaOH ------- > Na2ZnO2 + 2H2O

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Akshay Meena,
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M.Tech,IIT Kharagpur

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