Zn 2+ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M) 1) Zn(OH) 2 2) ZnO 3) Na 2 ZnO 2 4) all the above

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Akshay Meena · Answer

Zn+2 + 2NaOH -----> Zn(OH)2 + 2Na+
Zinc Hydroxide dissolve in excess alkali because it is also an amphoteric hydroxide and therefore reacts to form solumble Sodium Zincate.
Zn(OH)2 + 2NaOH ------- > Na2ZnO2 + 2H2O

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Zn 2+ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M) 1) Zn(OH) 2 2) ZnO 3) Na 2 ZnO 2 4) all the above

Zn²⁺ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M)

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Zn 2+ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M) 1) Zn(OH) 2 2) ZnO 3) Na 2 ZnO 2 4) all the above

Zn2+ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M)

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Zn²⁺ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M)