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Zn2+ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M)

1) Zn(OH)2

2) ZnO

3) Na2ZnO2

4) all the above

sneha singh , 12 Years ago
Grade 12
anser 1 Answers
Akshay Meena
Zn+2 + 2NaOH -----> Zn(OH)2 + 2Na+
Zinc Hydroxide dissolve in excess alkali because it is also an amphoteric hydroxide and therefore reacts to form solumble Sodium Zincate.
Zn(OH)2 + 2NaOH ------- > Na2ZnO2 + 2H2O
Thanks & Regards
Akshay Meena,
askIITians Faculty
M.Tech,IIT Kharagpur

Last Activity: 12 Years ago
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