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Zn 2+ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M) 1) Zn(OH) 2 2) ZnO 3) Na 2 ZnO 2 4) all the above

Zn2+ dissolves in excess of NaOH due to the formation of:(EAMCET 1992 M) 


1) Zn(OH)2 


2) ZnO 


3) Na2ZnO2 


4) all the above

Grade:12

1 Answers

Akshay Meena
askIITians Faculty 34 Points
7 years ago
Zn+2 + 2NaOH -----> Zn(OH)2 + 2Na+
Zinc Hydroxide dissolve in excess alkali because it is also an amphoteric hydroxide and therefore reacts to form solumble Sodium Zincate.
Zn(OH)2 + 2NaOH ------- > Na2ZnO2 + 2H2O
Thanks & Regards
Akshay Meena,
askIITians Faculty
M.Tech,IIT Kharagpur

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