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XY2 dissociates as XY2 (g) gives XY(g)+Y(g) When the initial pressure of XY2 is 600mmHg ,the total equilibrium pressure is 800mmHg.calculate Kp for the reaction assuming that the volume of the system remains unchanged.
Initial pressure a = 600 mm Hg XY2 (g) --------------------------> XY(g) + Y(g) at equilibrium a - x x xat equilibrium total pressure ( a - x + x + x) =800 mm Hg 600 + x = 800 x = 200 Kp = Pxy * Py / Pxy2 = 200 * 200 / 400 = 100 mm Hg = 100 / 760 atm = 0.132 atm
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