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XY2 dissociates as XY2 (g) gives XY(g)+Y(g) When the initial pressure of XY2 is 600mmHg ,the total equilibrium pressure is 800mmHg.calculate Kp for the reaction assuming that the volume of the system remains unchanged. XY2 dissociates asXY2 (g) gives XY(g)+Y(g)When the initial pressure of XY2 is 600mmHg ,the total equilibrium pressure is 800mmHg.calculate Kp for the reaction assuming that the volume of the system remains unchanged.
Initial pressure a = 600 mm Hg XY2 (g) --------------------------> XY(g) + Y(g) at equilibrium a - x x xat equilibrium total pressure ( a - x + x + x) =800 mm Hg 600 + x = 800 x = 200 Kp = Pxy * Py / Pxy2 = 200 * 200 / 400 = 100 mm Hg = 100 / 760 atm = 0.132 atm
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