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Grade: 12th pass

                        

XY2 dissociates as XY2 (g) gives XY(g)+Y(g) When the initial pressure of XY2 is 600mmHg ,the total equilibrium pressure is 800mmHg.calculate Kp for the reaction assuming that the volume of the system remains unchanged.

2 years ago

Answers : (1)

Arun
24742 Points
							
Initial pressure  a = 600 mm Hg 
                      XY2 (g) -------------------------->  XY(g)  +  Y(g)
 at equilibrium  a - x                                     x            x
at equilibrium total pressure  ( a - x + x + x)  =800 mm Hg
                                           600 + x = 800
                                               x = 200
 Kp  =  Pxy * Py / Pxy2
        =   200 * 200 / 400
        =  100 mm Hg 
        =   100 / 760 atm
        =   0.132 atm   
2 years ago
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