Why we are considering the contribution of d electron as (5×0.35) for the 4s electron of Chromium and in Cu we are taking the contribution of d as (18×0.85).?

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Why we are considering the contribution of d electron as (5×0.35) for the 4s electron of Chromium and in Cu we are taking the contribution of d as (18×0.85).?

Why we are considering the contribution of d electron as (5×0.35) for the 4s electron of Chromium and in Cu we are taking the contribution of d as (18×0.85).?

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Why we are considering the contribution of d electron as (5×0.35) for the 4s electron of Chromium and in Cu we are taking the contribution of d as (18×0.85).?

Why we are considering the contribution of d electron as (5×0.35) for the 4s electron of Chromium and in Cu we are taking the contribution of d as (18×0.85).?

1 Answers

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