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Grade 11Inorganic Chemistry

When AgNO3 was treated with 5.08g of a sample of iron chloride, 11.48g of AgCl was formed. 6.51g of another iron chloride gave 17.22g of AgCl on treatment with AgNO3. Show that these results illustrate the law of multiple proportions.

Profile image of AUM
7 Years agoGrade 11
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1 Answer

Profile image of Arun
6 Years ago
For 1st case, xAgNO3​+FeClx​→xAgCl
1 mol of FeClx​ gives x moles of AgCl.
∴56+35.5x5.08​mol gives 56+35.5x5.08​molesAgCl
∴56+35.5x5.08​=143.511.48​
⇒x=2
 
For 2nd case, yAgNO3​+FeCly​→yAgCl
1 mol of FeCly​ gives y moles AgCl
∴56+35.5y6.51​mol gives 56+35.5y6.51​molesAgCl
∴56+35.5y6.51​=143.517.22​=0.12
⇒y≈3
⇒yx​=32​→ This is in accordance with law of proportions.

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