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Grade 12th passInorganic Chemistry

When a solution of propionic acid is half neutralized with NaOH, the pH equals
4.87. what is the dissociation constant of acid?
246

Profile image of ajay
9 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
9 Years ago
Already Answered this qstn.
Plz do check your prevvious one!
 
Half of propanoic acid gets neutralized.
Hence for a mol of propanoic acid a/2 mol left.
 
4.87 = -log[H+]
-log((ka * CH3 – CH2 – COOH)/(CH3COO-)) = 4.87
On solving we get,
Ka = 10^-4.87/2.
 

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